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The assignment variables are as follows:
1) The base rate is 5 percent of the car value
2) If the person is younger than 24, add on 15% of the base rate to the total rate
3) If the person is between 25 and 29, add on 10% of the base rate to the total rate
4) If the person is older than 30, it's just the base rate
5) If the person has 1 ticket, add 10% to the age rate
6) If the person has 2 tickets, add 25% to age rate
7) If the person has 3 tickets, add 50% to age rate (sucks for them)
8) If the person has 4 tickets, deny them coverage (muhahahaha)
Ok, so that's it. Sounds simple, right? Well, maybe it is, but for someone without a programming background, this is tough.
Ok, so our teacher said to break it down piece by piece. Get it working, then simplify.
I'm also supposed to use "Switch," "If," and "Else" which I don't completely understand yet. Hopefully by the end of this post, I will get it.
============
Integer inputs needed to solve problem (cin >>)
Int CarValue
Int Age
Int NumberOfTickets
============
Other Integers
AgeRate
FinalRate
============
Breaking down the math...
BASE RATE
BaseRate=(CarValue*.05)
AGE RATE
If Age is <=24 AgeRate=BaseRate+(BaseRate*.15)
//if age is less than or equal to 24
AgeRate = CarValue*.05+(Car Value *.05 * .15)
AgeRate = Car Value * .05 + Car Value * .0075
AgeRate = Car Value * .0575
If Age is >=25 and <=29 AgeRate=BaseRate+(BaseRate*.10)
//if age is greater than or equal to 25 and less than or equal to 29
AgeRate = CarValue*.05 + (Car Value *.05 *.10)
AgeRate = Car Value * .05 +Car Value *.005
AgeRate = Car Value *.055
FINAL (TICKETS) RATE
If NumberOfTickets = 0
FinalRate = AgeRate
If NumberOfTickets = 1
AgeRate*1.10
If NumberOfTickets = 2
AgeRate*1.25
If NumberOfTickets = 3
AgeRate*1.50
If NumberOfTickets >=4
Denied. Sucka.
=====================
/* Ok, good, I think the math is right there. Now I just have to figure out how to write this program. This is the part where I get really lost. Let's see...*/
===============
Understanding If and Else and the "Logical Operators" (And, Or, Not)
Even though ultimately I want to write this program using Switch, I need to understand If and Else, which is what I'd use if I couldn't simplify with Switch.
//stolen from textbook
"The if statement enables you to test for a condition and branch to different parts of your code, depending on the result. The simplest form:
if (expression)
statement;
The expression in the parentheses can be any expression, but usually contains one of the relational expressions. If the expression has the value false, the statement is skipped. If it's true, it's executed.
if (bigNumber > smallNumber
bigNumber = smallNumber;
So...
{
if (age<=24);
ageRate=(carValue*.0575);
}
{
if ((age=>29) && (age=<24));
ageRate=(carValue*.055);
{
else
ageRate=baseRate;
}
// the logical operators: (And = && ) (Or= ||) ( Not= !)
==============
Let's Switch
Ok, so I'm not sure if I'm supposed to use Switch for just number of tickets, or if I should use it for the ageRate too. Hmm...
First, let me see if I can figure out "Switch."
Stolen from the textbook:
"Unlike if, which evaluates one value, switch statements enable you to branch on to any of several values. The general form of the switch statement is:
switch (expression)
{
case valueOne: statement;
break;
case valueTwo: statement;
break;
default: statement
break;
}
expression is any legal C++ expression, and the statements are any legal C++ statements. If one of the case values matches the expression, program execution jumps to those statements and continues to the end of switch block, unless a break statement is encountered." Also, if nothing matches, it goes to the optional default statement || no default exists and execution falls through switch commands and basically ignores them.
/* Now what's confusing me the most is figuring out where I define what the case is. Also, does it make sense to do Switch for ageRate or is that simple enough that it doesn't need switch? I guess I might be able to make the entire program written in one switch statement, but I'm not sure how I'd do that. Good thing I have all of Sunday afternoon and unlimited blog space to figure this out
Maybe the case name doesn't matter, you just have to label it.
*/
/*ugh*/
/*$*!@*/
/* 30 minutes later. Ok, I'm not getting this. I'm going to try a different approach, starting with the beginning of the program and asking for inputs, then seeing how I can apply switch to them */
#include
using namespace std;
int main(void)
{
int carValue;
cout << "Enter your car value: ";
cin >> carValue;
float baseRate = (carValue*.05)
switch (ageRate)
case
/*huh?*/
/*Google searching "complex switch C++"*/
/*FINALLY figured out what was confusing me... thanks to a devmaster.net thread ... "You can't use ranges in switch statements. Not supported by the language, sorry." Ooooh. So, I can't switch for AgeRate BUT I can for Tickets since that's just a number. OMG. No wonder I was confused. Let's see if this works.*/
#include
using namespace std;
int main(void)
{
int carValue;
int age;
int numberOfTickets
cout << "Enter your car value: ";
cin >> carValue;
cout << "Enter your age: ";
cin >> age;
cout >> "How many tickets have you received?";
cin >> numberOfTickets
float baseRate = (carValue*.05)
{
if (age<=24);
ageRate=(carValue*.0575);
}
{
if ((age=>29) && (age=<24));
ageRate=(carValue*.055);
{
else
ageRate=baseRate;
}
switch (finalRate)
{
case 0: cout >> "Your annual insurance rate is "ageRate<<"\n;
break;
case 1: cout >> "Your annual insurance rate is "ageRate*1.10<<"\n;
break;
case 2:cout >> "Your annual insurance rate is "ageRate*1.25<<"\n;
break;
case 3:cout >> "Your annual insurance rate is "ageRate*1.50<<"\n;
}
{
if numberOfTickets =>4;
cout >> "Hop on a bike. You are so denied.";
}
/*this is probably incorrect but at the very least I have the start of a program that could feasibly work. Time to move it over to the compiler and see what happens. Holding breath.*/
=========================
If Debugging=Fun cout>>"Liar."
Running program in xcode for error search...
Well, that only had 14 errors and 4 warnings. :) Time to get down to the real work.
#include expects "FILENAME" or
ok, so I copied that top from some blog somewhere. I'm replacing with the top part I used in my last assignment that seemed to work fine.
Down to 12 errors but now at 6 warnings.
Expected initializer before 'cout' for cout << "Enter your care value: ";
I forgot a semicolon...
Now at 11 errors and 7 warnings, huh?
Unused variable: carValue
but I do use it. Or maybe it has to be within the same brackets. Getting rid of the ints I'm defining up top...
10 errors, 4 warnings...
Expected constructor, destructor, or type conversion before '>>' token
Moved the ints to the same place i'm asking for cins and the program seems to like that.
9 errors, 4 warnings...
No match for 'operator>>' in'std::cout>> "How many tickets have you received?"
arrows going wrong way, duh. also adding semicolon I'm missing on next line...
7 errors, 4 warnings
'carValue' was not declared
have a feeling this has to do with brackets
6 errors, 4 warnings...
no, wait... 9 errors, 4 warnings... what???
Expected unqualified-id before '{' token
... down to 4 warnings with the following code:
#include
#include
using namespace std;
int main ()
{
int carValue, age, numberOfTickets;
cout << "Enter your car value: \n";
cin >> carValue;
cout << "Enter your age: \n";
cin >> age;
cout << "How many tickets have you received? \n";
cin >> numberOfTickets;
float baseRate;
baseRate = (carValue*.05);
float ageRate;
if (age<=24)
ageRate=(carValue*.0575);
else if ((age<=24) && (age>=29))
ageRate=(carValue*.055);
else
ageRate=baseRate;
float finalRate
switch (finalRate)
{
case 0: cout << "Your annual insurance rate is ageRate \n";
break;
case 1: cout << "Your annual insurance rate is >> ageRate*1.10 \n";
break;
case 2:cout << "Your annual insurance rate is >> ageRate*1.25 \n";
break;
case 3:cout << "Your annual insurance rate is >> ageRate*1.50 \n";
break;
}
if (numberOfTickets >=4)
cout << "Hop on a bike. You are so denied.";
return 0;
}
================
/*more when i get this figured out*/
